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OpenStudy (anonymous):
If I have a tube with ID 4” and length of 55” how can I calculate the inter surface of it assuming it is a flat sheet
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OpenStudy (anonymous):
the inner surface will be the surface area of a cylinder. I believe the formula is pi*radius*hieght so the answer would be 55*4*pi == 220pi
OpenStudy (dumbcow):
Surface area of cylinder = 2*pi*r*h im assuming ID means inner diameter radius = 1/2*diameter SA = 2*2*55*pi SA = 220pi
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