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Can anyone help me solve these 2 Quadratic equations ? x^2 – 36 = 0 and x^2 = 8x – 12
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1)x=+6 or x=-6
x^2=36 X=+6,-6
2)x^2-8+12=0 x^2-6x-2x+12=0 x(x-6)-2(x-6)=0 (x-2)(x-6)=0 x=2 x=6
I think its x^2 - 8 - 12 Not +12
no it is x^2-8x+12
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1)x^2=36 x=+6,-6 2)^2-8+12=0 x^2-6x-2x+12=0 x(x-6)-2(x-6)=0 (x-2)(x-6)=0 x=2 x=6
oh ok
they added 12 on both sides to cancel it on the right side and move it to left side
:)
any other question
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No i am good for now thanks! :) you are all my Heros!!!!! :)
x^2 – 36 = 0 x^2=36 x=6 or -6
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