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Mathematics 15 Online
OpenStudy (anonymous):

find the derivative of sqrt(tan^2x)

OpenStudy (anonymous):

If this is: \[\sqrt{tan^2(x)}\] Then you simplify first to: \[tan(x)\] and derive to \[sec^2(x)\] Seems a bit simple though so perhaps I'm misreading it?

OpenStudy (anonymous):

ya it is the same\[\sqrt{\tan^2x}\]

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