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OpenStudy (anonymous):
solve 3x+2/x-1=3x+4/x+1
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OpenStudy (anonymous):
x = -3/2
OpenStudy (anonymous):
Common Denomiator:(x+1)(x-1)
OpenStudy (anonymous):
((x+1)(3x+2))/(x-1)(x+1) = (3x+4)(x-1)/(x+1)(x-1) (x+1)(3x+2) = (3x+4)(x-1) Now, solve.
OpenStudy (anonymous):
x = -1
OpenStudy (anonymous):
x = -3/2
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OpenStudy (anonymous):
my fault i did it backwards... x = -1.5 or -3/2
OpenStudy (anonymous):
it is so siple dude..just cross multiply u will got a quadratic equation..and just solve that
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