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integrate ((2x^3 - 12x)^300)(x-2) dx?
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\[1/1806(2x ^{3}-12x)^{301}+c\]
I'm not sure how you did that..
Unless that is supposed to be (x^2-2) on the end there.
I am so confused too polpak Wolfram even times out: http://www.wolframalpha.com/input/?i=integrate+%28x-2%29*%282x^3-12x%29^300
If it's x^2-2 on the end then a u-sub works fine. Otherwise it's a mess.
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Indeed. lol
NO. du=6x^2-12
Uh.. du does not equal 6x-12. It equals 6x^2-12
Looks like a fun problem I'm on my iPhone and at a meeting though I'm not sure if this is am elementary integral or not but I wil think about it later
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