Mathematics
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OpenStudy (anonymous):
Use substitution to solve the system of equations.
5x + 5y = -30
2x - y = 15
(-2, 5)
(12, -5)
(3, -9)
(-2, 10)
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OpenStudy (anonymous):
<3 every one is looking at this question
OpenStudy (anonymous):
all 3 of us... :)
OpenStudy (anonymous):
there was like 5 of my friends looking now only 2 :(
OpenStudy (anonymous):
Isolate one of the variables in an equation
OpenStudy (anonymous):
what are the numbers in the () for?
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OpenStudy (anonymous):
think those are answer choices
OpenStudy (anonymous):
Let me post ss
OpenStudy (anonymous):
Yes they are gand
OpenStudy (anonymous):
In the 2nd x=15+y/2 Take that x to the 1st
OpenStudy (anonymous):
3,-9
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OpenStudy (anonymous):
So... first, isolate a variable.
lets do x caus x is fun
5x+5y=-30
5x=-30-5y
x=-6-y
OpenStudy (anonymous):
(3, -9)
OpenStudy (anonymous):
now, wherever u c an x in the second equation, plug in -6-y
solve for y
OpenStudy (anonymous):
OpenStudy (anonymous):
2(-6-y)-y=15
-12-2y-y=15
-12-3y=15
-3y=27
y=-9
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OpenStudy (anonymous):
Now plug that into an equation and solve for x
OpenStudy (anonymous):
:O you lost me
OpenStudy (anonymous):
which part?
OpenStudy (anonymous):
idk where you got 2(-6-y)-y=15
-12-2y-y=15
OpenStudy (anonymous):
whats 2*-6 and 2*-y
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OpenStudy (anonymous):
it's and x not *
OpenStudy (anonymous):
okay... you see where I got the first equation equal to x?
x=-6-y
-6-y is x
so wherever u see an x, u can put in -6-y, because they're the same thing
OpenStudy (anonymous):
got it or still confused or did I do the wrong part...
OpenStudy (anonymous):
i think i got it but i don't get how to go from there :'(
OpenStudy (anonymous):
okay.
2x-y=15
2(-6-y)-y=15
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OpenStudy (anonymous):
distribute the 2
OpenStudy (anonymous):
(3,-9)
OpenStudy (anonymous):
-12-2y-y=15
OpenStudy (anonymous):
with me so far?
OpenStudy (anonymous):
i kinda am lost on the steps but i kinda get what your doing
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OpenStudy (anonymous):
K. want me to back up and show you again or keep going?
OpenStudy (anonymous):
:S idk brb i have to help my dad -_-
OpenStudy (anonymous):
k, c u l8r