Question

What is the length of the focal width?

x=(1/4)y^2

Answer 1

=1/4a
where a = 1/4

Answer 2

so the answer is 1/4?

Answer 3

substitute 1/4 for a
\[\frac{1}{4*(1/4)} = 1\]
focus at (1,0)

Answer 4

thanks!