Question

2x^2-8x=-8

Answer 1

2x^2-8x+8=0
2(x^2-4x+4)=0
2(x-2)^2=0

x=2 d.r (double root)

I don't know if you learned double root, but if you didn't don't add that.

Answer 2

pretty sure they'd use the quadratic formual

Answer 3

x2-4x+4=0 x=2

Answer 4

dont i need to answers like x = __or __

Answer 5

yes, but in this case, x can only equal one number, which is 2.

Answer 6

oh ok thank you guys!!!!!!

Answer 7

:) np. glad to help you with the past 10 questions xDD :P

Answer 8

D= 16-4*1*4=0 so x1,2= 4+-0/2 so 2

Answer 9

dude...just factor it lol.