Question

In the system shown below, what are the coordinates of the solution that lies in quadrant II?

x^2+4y^2=800
y=(1/32)x^2

Answer 1

Maybe u can mange this one by yourself...

Just sub the bottom into the top, u get a quartic in x and set x^2 = z to get a quadratic and solve.

Take the minus solution and sub back into the second for y, will be in quadrant 2.

(too many roots and numbers for my taste, I will make mistakes).