Question

solve the following system of equations:
use the substitution method{5x+6y+8=0
{3x-2y+16=0

Answer 1

Re-write equation 1, solving for y
5x+8=-6y
6y= -8 - 5x
y= -4/3 - 5x/6

Now substitute this value for y into the second equation so that
3x-2y+16=0, becomes
3x-(-4/3 - 5x/6) +16 = 0, then expand the negative sign into the brackets
3x +4/3 +5x/6 +16 = 0, Simplify
23x/6 + 52/3 = 0
23x/6 = -52/3
23x/2 = -52
23x = -104
x = -104/23

Answer 2

Then substitute that value for x back into the first equation to find y
y=-4/3 - x/6