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apply the quadratic formula to find the roots of the given function, and then graph the function. f(x) = y2 - 9 show work please
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(y+3)(y-3) so y=3 and y=-3 which are the roots
do u know the formula for the quadratic equation
Yes, \[-b \pm \sqrt{b ^{2}-4ac}/2a\]
not sure how \[f(x)=y^2-9\] makes sense
if it is \[f(x)=x^2-9\] then the solutions to \[x^2-9=0\] are 3 and -3 with your eyeballs, not with any formula \[x^2-9=0\] \[x^2-9\] \[x=\pm3\]
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thanks!!!
yw
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