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What is the sum of the angle measures in a polygon that has 20 sides?
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use the formula.
\[(x-2)*180\]
where x is the number of sides.
are the number of sides*
180(x-2) 180(18) 3240degrees
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Runner, no it isnt. LOL.
its for 4 sided.
Sum of exterior angles of any polygon is 360 degrees. Each exterior angle of a regular polygon = 360/n where n is the number of sides. So, n = 360/20 = 18. OR Each interior angle of the regular polygon is 180-20 = 160 degrees So, sum of interior angles of the regular polygon = 160n degrees where n is the number of angles (also the number of sides) Now, sum of interior angles of any polygon = (n-2)x180 degrees Thus 160n = (n-2)x180 or 160n = 180n - 360 Solving for n, we get n = 18.
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