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what is the minimum value of -x^2+1?
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an upside down parabola has no minimum value
our teacher insists there's something with infinity... i forgot what exactly. i'm trying to remember.
it extend doward towards -inf ; but whether or not that can be considered a minimum value i can recall
-inf is not reachable so it has no minimum in that sense
-(x^2)
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Actually, our teacher claims it's a very, very small number. D':
tell him its dy :)
[1,-inf) is proper
but that is range, not minimum
whoops accidentally deleted my comment but all right! thanks.
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