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Mathematics 19 Online
OpenStudy (aravindg):

HI HERE IS A NEW PROBLEM WITH PICTURE

OpenStudy (anonymous):

where is the pic

OpenStudy (anonymous):

I am waiting

OpenStudy (aravindg):

1.Which way will system move ? 2.what is acceleration of blocks? 3.What is tension in chord?

OpenStudy (aravindg):

OpenStudy (aravindg):

working???

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

is there friction

OpenStudy (aravindg):

no

OpenStudy (aravindg):

NO FRICTION

OpenStudy (anonymous):

cos 53

OpenStudy (aravindg):

????

OpenStudy (anonymous):

in left direction

OpenStudy (aravindg):

plz giv steps and answer for 3 questions above

OpenStudy (anonymous):

oh one more wedge joint or free to move

OpenStudy (anonymous):

can the wedge move ?

OpenStudy (aravindg):

no

OpenStudy (anonymous):

then just apply take the pulling force of the two blocks and subtract them

OpenStudy (aravindg):

giv answer in steps plzzzzzzzzzzzzzz

OpenStudy (anonymous):

like for the left block pulling force is 100xrad3/2

OpenStudy (anonymous):

I will try to work it out on paper

OpenStudy (anonymous):

i did that already system will move in left direction .

OpenStudy (aravindg):

y??? plzz giv steps

OpenStudy (aravindg):

1.Which way will system move ? 2.what is acceleration of blocks? 3.What is tension in chord?

OpenStudy (anonymous):

50rad3 > 50 x .60 thats why

OpenStudy (anonymous):

sytem will move in left or wait a minute i will attach something

OpenStudy (anonymous):

t - 50rad3 = -100a t - 50 x .6 = 50a

OpenStudy (anonymous):

now t = 50rad3 -100a 50rad3 -100a -50x.6 = 50a solve this to get a

OpenStudy (anonymous):

then put the value of a in t equation to get t

OpenStudy (anonymous):

now solve it and tell me is it right

OpenStudy (aravindg):

is it???

OpenStudy (anonymous):

i didn't get you ...my equations must be right now all you have to do is solve thats all

OpenStudy (aravindg):

rad means

OpenStudy (anonymous):

oh ...rad is for sqrt (square root )this 53 angle is complicating things

OpenStudy (anonymous):

\[F_{100}:\] \[F_x=-cos 30 mg + T\] \[N=sin 30 mg \] \[F_{50}:\] \[F_x=-cos 53 mg + T\] \[N=sin 53 mg \]

OpenStudy (aravindg):

here

OpenStudy (anonymous):

so tell us .....it must be right .

OpenStudy (aravindg):

actually i dont knw answer thts y i asked

OpenStudy (anonymous):

so don't worry ..what imran did is correct

OpenStudy (aravindg):

is thtat the tension in chord???

OpenStudy (anonymous):

yes

OpenStudy (aravindg):

what about a??

OpenStudy (aravindg):

........

OpenStudy (anonymous):

you have to use substitution to find a

OpenStudy (aravindg):

k ....its genius

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