Mathematics
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OpenStudy (aravindg):
HI HERE IS A NEW PROBLEM WITH PICTURE
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OpenStudy (anonymous):
where is the pic
OpenStudy (anonymous):
I am waiting
OpenStudy (aravindg):
1.Which way will system move ?
2.what is acceleration of blocks?
3.What is tension in chord?
OpenStudy (aravindg):
OpenStudy (aravindg):
working???
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
is there friction
OpenStudy (aravindg):
no
OpenStudy (aravindg):
NO FRICTION
OpenStudy (anonymous):
cos 53
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OpenStudy (aravindg):
????
OpenStudy (anonymous):
in left direction
OpenStudy (aravindg):
plz giv steps and answer for 3 questions above
OpenStudy (anonymous):
oh one more wedge joint or free to move
OpenStudy (anonymous):
can the wedge move ?
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OpenStudy (aravindg):
no
OpenStudy (anonymous):
then just apply
take the pulling force of the two blocks and subtract them
OpenStudy (aravindg):
giv answer in steps plzzzzzzzzzzzzzz
OpenStudy (anonymous):
like for the left block pulling force is 100xrad3/2
OpenStudy (anonymous):
I will try to work it out on paper
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OpenStudy (anonymous):
i did that already system will move in left direction .
OpenStudy (aravindg):
y??? plzz giv steps
OpenStudy (aravindg):
1.Which way will system move ?
2.what is acceleration of blocks?
3.What is tension in chord?
OpenStudy (anonymous):
50rad3 > 50 x .60
thats why
OpenStudy (anonymous):
sytem will move in left or wait a minute i will attach something
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OpenStudy (anonymous):
t - 50rad3 = -100a
t - 50 x .6 = 50a
OpenStudy (anonymous):
now t = 50rad3 -100a
50rad3 -100a -50x.6 = 50a
solve this to get a
OpenStudy (anonymous):
then put the value of a in t equation to get t
OpenStudy (anonymous):
now solve it and tell me is it right
OpenStudy (aravindg):
is it???
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OpenStudy (anonymous):
i didn't get you ...my equations must be right now all you have to do is solve thats all
OpenStudy (aravindg):
rad means
OpenStudy (anonymous):
oh ...rad is for sqrt (square root )this 53 angle is complicating things
OpenStudy (anonymous):
\[F_{100}:\]
\[F_x=-cos 30 mg + T\]
\[N=sin 30 mg \]
\[F_{50}:\]
\[F_x=-cos 53 mg + T\]
\[N=sin 53 mg \]
OpenStudy (aravindg):
here
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OpenStudy (anonymous):
so tell us .....it must be right .
OpenStudy (aravindg):
actually i dont knw answer thts y i asked
OpenStudy (anonymous):
so don't worry ..what imran did is correct
OpenStudy (aravindg):
is thtat the tension in chord???
OpenStudy (anonymous):
yes
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OpenStudy (aravindg):
what about a??
OpenStudy (aravindg):
........
OpenStudy (anonymous):
you have to use substitution to find a
OpenStudy (aravindg):
k ....its genius