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Mathematics 9 Online
OpenStudy (anonymous):

how would you factor 15v^3+35v^2+21v+49? Please answer...

OpenStudy (anonymous):

we can factor this: first: we group: (15v^3+35v^2)+(21v+49) Next factor out terms: 5v^2(3v+7)+7(3v+7) Finally: (5v^2+7)(3v+7)

OpenStudy (anonymous):

v (v (15 v+35)+21)+4 Alternate Form

OpenStudy (anonymous):

It is, who said it isn't.

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