Question

find the center and the radius of the circle whose equation (x-3)^2 + (y+4)^2=16

Answer 1

its right there in the equation ....

Answer 2

-(-3,4)

Answer 3

radius 4

Answer 4

radius = sqrt 16 = 4

Answer 5

this is designed to get you to see into the equation at its relevant parts ....

Answer 6

(3,-4)
4 unit

Answer 7

(x-Cx)^2 + (y-Cy)^2 = r^2


where; center is (Cx,Cy) and radius = r