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Solve. (3x^2)=33x+24 1) 11±√156 / 2 2) 11≠√89 / 2 3) -11± (3√89) / 2 4) -11± (9√17) / 2
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so would that be number 4?
\[11\pm 3\sqrt{17}\div2\]
r u sure u have these options.check again please
ok one sec
1) should be 11±√153 / 2
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2) 11±√89 / 2
\[\sqrt{153\[\neq \sqrt{89}\]
i think the answers are not correct
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