Question

find max and min value of f(x) = 2x^2-8x+1 by completing the square. show work please

Answer 1

completing squares I don't know that method I will like to see how it's done

Answer 2

f(x)=2(x^2-4x+4)-7
=2(x-2)^2-7
so (x-2)^2 is always +ve so f(x)min = -7 and f(x) max is infinity

Answer 3

f(x) has no maximum.

Answer 4

your statement is partially correct @pol f(x) has no finite maximum thats why i wrote f(x) max is to be infinite