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Please help:Solve. (2x^2) - 8x -14 = 0 1) x= 4± 3 √2 2) x= 4± √3
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\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
I tried doing that, i got down to 4±√44 / 2
\[x = \frac{ 8 \pm \sqrt{64 + 14 \times 4}}{4}\]
try it now
8±√78 ?
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is it 1 or 2 can you please help ):
8±√120/4
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