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solve for θ: csc^2θ=cotθ+1
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\[ \frac{1}{sina} = \frac{cosa + sina}{sina}\]
No pi. pi in the cosine gives -1.
ah i didn't see that it's cos^2
\[\frac{1}{sin^2a} = \frac{cosa+sina}{sina}\] \[1 = sinacosa + sin^2a\] a = pi/2
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