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Mathematics 19 Online
OpenStudy (anonymous):

Factor completely x2 – 4x – 12

OpenStudy (anonymous):

(x -6)(x+2)

OpenStudy (anonymous):

(x-6)(x+2)

OpenStudy (anonymous):

ishaan - u type too fast!!!

OpenStudy (anonymous):

do u understand how we got that answer lisa?

OpenStudy (anonymous):

\[x^2-6x+2x-12\] \[x(x-6)+2(x-6)\] \[(x+2)(x-6)\]

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