Question

how do you factor t^3-t=0

Answer 1

t(t+1)(t-1)

Answer 2

how did you do that?

Answer 3

\[t[t^2-1]\]
\[t[(t)^2-(1)^2]\]
\[a^2-b^2=(a+b)(a-b)\]
so
\[t(t+1)(t-1)\]