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Mathematics 24 Online
OpenStudy (anonymous):

3/x + 2/x+2 How do i do this?

OpenStudy (anonymous):

3/x + 2/x+2 (3+2+2x)/x (5+2x)/x

OpenStudy (anonymous):

5/x+2 x=-5/2

OpenStudy (anonymous):

(5/2x) + 2

OpenStudy (anonymous):

OpenStudy (anonymous):

\[5x+6/(2x+1)(x+2)\]

OpenStudy (anonymous):

(3(x+2)+2x)/(3x-2(x+2)) (5x+6)/(x-4)

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