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what is the simplified form of y^2-y-12 overY^2+8y+15
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(y-4)(y+3)/(y+5)(y+3) (y-4)/(y+5)
\[\left[\begin{matrix}y^2-y- & 12 \\ y^2=+8y & +15\end{matrix}\right]\]
(y-4)(y+3)/(y+3)(y+5) =y-4 over y+5
factor the top and bottom then cancel the y+3
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