Question

Help me please

Trains A and B are traveling in same direction on parallel tracks. Train A is traveling at 80mph, and train B is traveling at 84 mph. Train A passes a station at 2:10am. If train B passes the same station at 2:40am what time will train B catch up with train A?

Answer 1

For this problem we use the problem rate * time = distance.
If t represents the time that train B travels from the station until they catch up, then train A will have a time of (t+0.5) to travel that same distance.

Answer 2

For train A: distance = 80 * (t + 0.5)
For train B: distance = 84 * t
Since the distance from the station they pass to where they catch up is the same distance, we can set the two expressions equal to each other.
80(t + 0.5) = 84t

Answer 3

-10?

Answer 4

You should get a positive 10.
t = 10

Answer 5

80t + 40 = 84t
40 = 4t
10 = t

Answer 6

-10?

Answer 7

so 10am?

Answer 8

Since t represents the time of train B, we add that time to 2:40am to get the time that the train B catches up to train A.

Answer 9

2:40am + 10 hours = 12:40pm

Answer 10

-10?

Answer 11

oh, I see