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what is f=x{98X-3x}4y is?
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What do you have to do with this?
I'm confused
Im confused too ^_
What are the directions?
Something about your set up doesn't appear to be right
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im sorry my professor doesn't give any direction... :(
The RHS reduces to:\[380 x^2 y \]
what is that can u explain that to me?
What? steps please?
?
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Wait...is the original problem f = x(98x - 3x)4y ?
Because if it is, then f = x(95x)4y = (95x^2)4y = 380x^2y
I was thrown off by the 98X - 3x
is that the answer?
apparently. I was just clarifying
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at least trying to
The problem statement capital X was changed to lower case x.\[x(98x-3x)4y \]\[\left(95 x^2\right)4y \]\[380 x^2 y \]
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