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What is the sum of a 10-term arithmetic sequence where the first term is 3 and the last term is 75?
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390
y10=y1+(10-1)*d 75=3+9d 9d=72 d=8 Sn=(y1+y10)*n/2=(3+75)*10/2=78*5=390
formula used n(a+l)/2 n=the number of terms a=1st term l=last term
sritama was correct, thank you :):)
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