Question

omg can someone solve this (with steps shown)
(x+6)(x-7)(x-8)(x+9)=0 by factoring?

Answer 1

that is factored

Answer 2

Already Factored!
x+6 = 0
x-7 = 0
x-8 = 0
x+9 = 0

Answer 3

factored already

Answer 4

x = -6, 7, 8, -9

Answer 5

the solutions of \[(x-a)(x+b)(x-c)(x+d)=0\] are
\[x=a,-b,c,-d\]