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Mathematics 20 Online
OpenStudy (anonymous):

Solve (x+19)(x-12)(x+6)>0 The solution set is {x|_}

OpenStudy (anonymous):

well, those are the roots of the polynomial, i would just test points in the intervals created by them. see where the graph is positive.

OpenStudy (across):

\[\left\{ x|x>12 \right\}\]

OpenStudy (anonymous):

x could also be between -19 and -6.

OpenStudy (anonymous):

so would it be {x|>12} or all real numbers?

OpenStudy (across):

It's the union of our sets :)

OpenStudy (anonymous):

lol yeah, its what across said :)

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