Question

in an isolated town of 5000 inhabitants,160 people have a disease at the beginning of the week and 1200 have it at the end of the week. How long does it take for 80% of the population to become infected?

Answer 1

80% of 5000 = 4000
160=beginning of the week(1day)
1200=end of the week (7days)
first 1200X4=4800 4week(28days)
160 + 4800 = 4960 too small
160 X 2 =320 (2days)
320 + 4800 = 5120 4 weeks and 2 days or (30days)

Answer 2

uh i gotta use differential equations to do it

Answer 3

what kind?

Answer 4

Ae^kt that one

Answer 5

oh

Answer 6

sorry man