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Let f(x) = 8x3 – 22x2 – 4 and g(x) = 4x – 3. Find f(x)/g(x)help please.
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Help me please
\[\Huge \frac{8x^3-22x^2-4}{4x-4}\]
Is that the final answer? I thought there was mre work.
*more
You can cancel a factor of 2, But otherwise that's pretty much it.
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Oh, no you can't because the g(x) isn't -4 it's -3
Saifoo screwed up in his haste.
I see. so more can be done?
Nope. Just the -4 in the denominator should be a -3
Are you sure that's it?
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If the original problem is as you have written it, yes.
I was asking is that right or not?
No it was -3 but thanks :)
the result is \[2x^{2} - 4x-3\] and rest is 5
@miss_maryyy
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