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OpenStudy (anonymous):
Which of the following is a solution to (√x+10)+8=3?
Answers: x = 15
x = 5
x = –5
x = –15
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OpenStudy (angela210793):
sqrx+10=-5
x+10=25
x=15
OpenStudy (anonymous):
it was for the previous equation also
OpenStudy (akshay_budhkar):
root of x+10=root 25=5+8=13
so angela you are wrong.
OpenStudy (anonymous):
agree with Akshay
OpenStudy (anonymous):
it will be x = 225
cause the result is
\[\sqrt{x}=-15\]
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OpenStudy (akshay_budhkar):
root of anything cannot be negative
OpenStudy (akshay_budhkar):
the answer to it is no solution..
i can bet.
OpenStudy (anonymous):
right answer 225
OpenStudy (angela210793):
wht?????????????????
subtract 8 both sides and u'll get sqr(x+10)=-5 raise to the 2nd power
x+10=(-5)^2=25
subtract 10
x=25-10
x=15
OpenStudy (akshay_budhkar):
sqr(x+10)=-5
this is wrong.
root cannot be negetive
check the graph of root x
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OpenStudy (angela210793):
sqr 25 may be -5 can't it?
OpenStudy (anonymous):
see the equation.
not whole squroot
only \[\sqrt{x}\]
OpenStudy (angela210793):
i know everything abt sqrx and its graph...
OpenStudy (akshay_budhkar):
no
sqr 25 cannot be -5
check the graph
OpenStudy (akshay_budhkar):
its always mod
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OpenStudy (angela210793):
well..why isn't thr any alternative no answer or smth like tht then? O.o
OpenStudy (akshay_budhkar):
no the answer is simply no solution if you go by rules
if the chapter or topic demands what you have done then it is right
mathematically its wrong
OpenStudy (angela210793):
i get ur point :)
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