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Mathematics 16 Online
OpenStudy (anonymous):

factor completely: 3p²-7p-6 Please explain how you did it! Thanks!

OpenStudy (anonymous):

Hi !

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

\[3p^2 -7p - 6\] \[3p^2 - 9p +2p - 6 \] \[3p(p -3) +2(p -3)\] \[(3p +2)(p-3)\]

OpenStudy (anonymous):

(p-3) (3 p+2) Ishaan94 gave work above, he is absolutely correct.

OpenStudy (anonymous):

But how did he do it?

OpenStudy (anonymous):

First, he split it onto 4 terms 3p^2 - 9p + 2p - 6 The, he factored. 3p(p-3) + 2(p-3) Then, he grouped. (3p +2)(p-3)

OpenStudy (anonymous):

I get that but where did he get the four terms?

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