A ball is thrown from an initial height of 3 ft with an initial upward velocity of 27ft/s The balls height h (in feet) after t seconds is given by the following. h=3+27t-16t^2. Find all values of t for which the balls height is 13 ft.

Question

anonymous · Answer

we are looking for values of t for which h=13
-16t^2+27t+3=13
or
-16t^2+27t-10=0

This is a quadratic equation with two solutions:
t1=(27 - sqrt(89))/32
t2=(27 + sqrt(89))/32

anonymous · Answer

Thank you I knew it involved quadratic equations but couldn't remember what to do and seeing as I dont have my calculus book...