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Mathematics 19 Online
OpenStudy (anonymous):

A truck can be rented from Basic Rental for $50 per day plus $0.20 per mile. Roadrunners charges $20 per day plus $0.50 per mile to rent the same truck. How many miles must be driven in a day to make the rental cost for Basic Rental a better deal than that for Roadrunners? step by step?

OpenStudy (anonymous):

50 + 0.2x = 20 + 0.5x Solve for x.

OpenStudy (saifoo.khan):

righto!^

OpenStudy (anonymous):

30 < .3x 100 < x or x > 100 You would need to drive over 100 miles per day to make Basic a better deal. You can easily check the answer by taking a number lower than 100 and inserting it for x and a number higher than 100 (and 100 if you want to confirm that the prices are = at that amt).

OpenStudy (anonymous):

so would x=9?

OpenStudy (anonymous):

50+.20X<20+.50X .20X-.50X<20-50 -.30X<-30 X>-30/-.30 NOTE: THE SIGN CHANGES WHEN DIVIDING BY A NEGATIVE VALUE

OpenStudy (anonymous):

X>100 GREATER THAN 100 MILES DRIVEN MAKES THE BASIC RENTAL OFFER A BETTER DEAL. PROOF: 50+.20*100<20+.50*100 50+20<20+50 70<70

OpenStudy (anonymous):

ok got it thanks...

OpenStudy (anonymous):

Glad to help

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