Question

Three consecutive odd integers are such that the square of the second is 96 less than the square of the third. Find the three integers

Answer 1

(x+2)^2 = (x+4)^2 - 96

Answer 2

Let the 3 odd integers be n, n+2, n+4
Set up equation
(n+2)^2=(n+4)^2-96

Answer 3

Wow Judith, I'm impressed

Answer 4

Thank you..

Answer 5

n^2++4n+4=n^2+8n+16-96
combine like terms
4n=84
n=21
the three integers are 21,23,25

Answer 6

I agree with Judith

Answer 7

Judith, did you get any help with the quadratic formula?

Answer 8

yes i did