Question

Solve. 2x^2 – 8x – 16 = 0

x = 2 ± 2 sqrt 3

x = 4 ± 2 sqrt 5

x = 2 ± 4 sqrt 2

x = 4 ± 2 sqrt 3

Answer 1

divide by 2 throughout. Then use

-b +- sqrt[b^2 - 4ac]
x = ---------------------
2a

Answer 2

It should be x=2±2sqrt3 if u use the quadratic formula

Answer 3

correct x = 2 ± 2 sqrt 3