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Find a polynomial for the perimeter and for area. The length of the rectangle is d+3 and the width is d. The perimeter is __ The area is __
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4d + 6
d^2 + 3d <--------area
given l=d+3 b=d area = l*b=d(d+3)\[=d ^{2}+3d\] primeter=2(l+b) =2(d+d+3)=4d+6
hope u have understood
Two different answers. Now I'm confused lol
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lol they are same
oops lol
but both are the same answer .
:)
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