Question

³√-216x³

I need help with this problem

Answer 1

first look at -216*x^3 as (-1)(x^3)*(6^3). Taking the third root you get x*6*thirdroot(-1)

-1=i^2 so thirdroot(-1) = thirdroot (i^2) = i^(2/3)
so full answer is 6x*i^(2/3)

Answer 2

the answer will be done like this
\[\sqrt[3]{-1}\sqrt[3]{216}\sqrt[3]{x ^{3}}\]
which will be -6x
i hope u understood