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Mathematics 13 Online
OpenStudy (anonymous):

logsin1degree logsin2degree .............. logsin179degree=

OpenStudy (dumbcow):

what do you need to know? is this supposed to be a sum?

OpenStudy (anonymous):

i dont know

OpenStudy (dumbcow):

well you can find log(sin@) by using a scientific calculator...

OpenStudy (anonymous):

it is in form loga.logb...... which is log(a+b+.....) hence log(sin1+sin2+sin3+.......+sin179) =log(sin0+sin1+....+sin179+sin180) =log(1) =0 hope u understood

OpenStudy (anonymous):

well this is a product of many terms which would be complicated except for the fact that sin(90 degrees) =0 so the whole product equals zero

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

*edit log(sin(90 degrees)=0

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