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solve:4^2x+6=1/16
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\[4^{2x+6}=1/16\] this one?
x=-95/256
then since \[4^{-2}=\frac{1}{16}\] you know that \[2x+6=-2\] solve for x
yeah the 1st one
you get \[2x=-8\] \[x=-4\]
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if 4^2(2x+6) else satellite's
thanx
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