Question

solve the system using the subtitution method
3x+6y=3
x-2y=5

Answer 1

Solve for y:
\[y = \frac{3-3x}{6}\]
\[y=-\frac{5-x}{2}\]
Substitute y = y:
\[\frac{3-3x}{6} = -\frac{5-x}{2}\]
Cross Multiply:
\[6(5-2x) = -2(3-3x) \]
Simplify:
\[30 -12x = -6 +6x \]\[36 = 18x \]\[x = 2 \]\[y = 1/2\]

Answer 2

Any questions?