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Mathematics 21 Online
OpenStudy (anonymous):

Factor the difference of squares: x^6-16x^4-81x^2+1296

jimthompson5910 (jim_thompson5910):

x^6-16x^4-81x^2+1296 x^4(x^2-16)-81(x^2-16) (x^4-81)(x^2-16) (x^2-9)(x^2+9)(x^2-16) (x-3)(x+3)(x^2+9)(x^2-16) (x-3)(x+3)(x^2+9)(x-4)(x+4) So x^6-16x^4-81x^2+1296 completely factors to (x-3)(x+3)(x^2+9)(x-4)(x+4) In other words, x^6-16x^4-81x^2+1296 = (x-3)(x+3)(x^2+9)(x-4)(x+4)

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