Question

Give exact and approximate solutions to three decimal places. X^2+8x+16=1
What are the exact solutions?

Answer 1

x^2+8x+16=1


(x+4)^2=1


x+4=sqrt(1)


x+4=1 or x+4=-1


x=1-4 or x=-1-4


x=-3 or x=-5

Answer 2

Very well put!