Question

x^2/(x^2-3) - (x+1)/(x+3) = 0, solve for x.....any help?

Answer 1

\[\frac{x^2}{x^{2}-3} - \frac{x+1}{x+3} = 0\]
\[\frac{x^2}{x^{2}-3} = \frac{x+1}{x+3}\]
cross-multiply
\[x^{2}(x+3) = (x+1)(x^{2}-3)\]
\[x^{3} +3x^{2} = x^{3}+x^{2}-3x-3\]
Combine like terms
\[2x^{2}+3x+3 = 0\]
Use quadratic formula
\[x = \frac{-3 \pm \sqrt{3^{2}-4(2)(3)}}{2(2)}\]
\[x = \frac{-3 \pm \sqrt{15}i}{4}\]
No real solution