Question

solve using the quadtratic formula

2x^2=4-7x

Answer 1

Put into standard form, ax^2 + bx + c = 0
2x^2 + 7x - 4 = 0
a = 2
b = 7
c = -4
Just plug it into the quadratic formula.

x = -4, 1/2

Answer 2

\[[-7\pm \sqrt{7^2-4*2*(-4)}]/2*2\]

Answer 3

\[(-7\pm \sqrt{81})/4\]

Answer 4

2x^2+7x-4=0
(2x-1)(x+4)=0
x=1/2,-4