Question

solve using the quadrtatic formula

x^2+5x-14=0

Answer 1

i got x=7 or 2 but it said it was wrong

Answer 2

formula is
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] put
\[a=1,b=5,c=-14\]

Answer 3

oh i see the problem

Answer 4

i thought you could factor?

Answer 5

(x-7)(x-2)

Answer 6

you can. factor as
\[(x+7)(x-2)=0\]

Answer 7

your sign was off.

Answer 8

oh ok thankyou :)

Answer 9

got it right?

Answer 10

should by -7 and 2

Answer 11

yes