Question

solve the linear system

3x-4y=8
4x+5y=10

Answer 1

multiply eq 1 by 5 and eq 2 by 4 then add both eq. we get
31x=80 or, x=80/31
substitute it in either equation and solve for y.

Answer 2

nvm

(3x-4y=8)5
(4x=5y=-10)4
-------------
15x-20y=40
16x+20=-40
-------------
31x=0
-- --
31 31
_______________
x=0

3(0)-4y=8
_______________
-4y=8
-- --
-4 -4
-------------
y=-2

Answer 3

In question's second eq there is +10 not -10.

Answer 4

oops! wrote it wrong the first few times.
4x+5y=-10.