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Find the solution to the equation 64^(x – 4) = 4^2x. Use complete sentences to explain the method used to solve this equation.
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4^3^(x-4) = 4^2x 4^3(x-4) = 4^2x 2x = 3(x-4) 2x = 3x - 12 -x = -12 x = 12
I think you're suppose to use log functions but I'm unsure how to work it out to get the right answer
Take the log of both sides. (x-4)log(4) 64 = 2x log(4) 4 3(x-4) = 2x Now, solve. x = 12
okay thank you!
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