Question

The graph of this quadratic function is a parabola. What is the x-coordinate of the vertex?

y=x^2+2x+1

Answer 1

-2 / 2

Answer 2

so x= -1

Answer 3

false

Answer 4

?

Answer 5

The Vertex is at
(-b/2a, f(-b/2a)) for any quadratic

Answer 6

vertex is (-1,0) what curry said. this is
\[y=(x+1)^2\]

Answer 7

i ented x=-1 and it was incoorrect tho

Answer 8

on line course is messed up then

Answer 9

ok thx anywya:)